4/(3x-2)=7/(2-5x)

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Solution for 4/(3x-2)=7/(2-5x) equation:


D( x )

2-(5*x) = 0

3*x-2 = 0

2-(5*x) = 0

2-(5*x) = 0

2-5*x = 0

2-5*x = 0 // - 2

-5*x = -2 // : -5

x = -2/(-5)

x = 2/5

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/5) U (2/5:2/3) U (2/3:+oo)

4/(3*x-2) = 7/(2-(5*x)) // - 7/(2-(5*x))

4/(3*x-2)-(7/(2-(5*x))) = 0

4/(3*x-2)-7*(2-5*x)^-1 = 0

4/(3*x-2)-7/(2-5*x) = 0

(4*(2-5*x))/((3*x-2)*(2-5*x))+(-7*(3*x-2))/((3*x-2)*(2-5*x)) = 0

4*(2-5*x)-7*(3*x-2) = 0

22-41*x = 0

(22-41*x)/((3*x-2)*(2-5*x)) = 0

(22-41*x)/((3*x-2)*(2-5*x)) = 0 // * (3*x-2)*(2-5*x)

22-41*x = 0

22-41*x = 0 // - 22

-41*x = -22 // : -41

x = -22/(-41)

x = 22/41

x = 22/41

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