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4/(5x)+1/10=3/(2x)
We move all terms to the left:
4/(5x)+1/10-(3/(2x))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/5x-(+3/2x)+1/10=0
We get rid of parentheses
4/5x-3/2x+1/10=0
We calculate fractions
20x^2/100x^2+80x/100x^2+(-150x)/100x^2=0
We multiply all the terms by the denominator
20x^2+80x+(-150x)=0
We get rid of parentheses
20x^2+80x-150x=0
We add all the numbers together, and all the variables
20x^2-70x=0
a = 20; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·20·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*20}=\frac{0}{40} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*20}=\frac{140}{40} =3+1/2 $
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