4/(7x-7)=8/(3x-3)

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Solution for 4/(7x-7)=8/(3x-3) equation:


D( x )

7*x-7 = 0

3*x-3 = 0

7*x-7 = 0

7*x-7 = 0

7*x-7 = 0 // + 7

7*x = 7 // : 7

x = 7/7

x = 1

3*x-3 = 0

3*x-3 = 0

3*x-3 = 0 // + 3

3*x = 3 // : 3

x = 3/3

x = 1

x in (-oo:1) U (1:+oo)

4/(7*x-7) = 8/(3*x-3) // - 8/(3*x-3)

4/(7*x-7)-(8/(3*x-3)) = 0

4/(7*x-7)-8*(3*x-3)^-1 = 0

4/(7*x-7)-8/(3*x-3) = 0

(4*(3*x-3))/((7*x-7)*(3*x-3))+(-8*(7*x-7))/((7*x-7)*(3*x-3)) = 0

4*(3*x-3)-8*(7*x-7) = 0

44-44*x = 0

(44-44*x)/((7*x-7)*(3*x-3)) = 0

(44-44*x)/((7*x-7)*(3*x-3)) = 0 // * (7*x-7)*(3*x-3)

44-44*x = 0

44-44*x = 0 // - 44

-44*x = -44 // : -44

x = -44/(-44)

x = 1

x in { 1}

x belongs to the empty set

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