4/(k-1)=6/(k-2)

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Solution for 4/(k-1)=6/(k-2) equation: 


D( k )

k-1 = 0

k-2 = 0

k-1 = 0

k-1 = 0

k-1 = 0 // + 1

k = 1

k-2 = 0

k-2 = 0

k-2 = 0 // + 2

k = 2

k in (-oo:1) U (1:2) U (2:+oo)

4/(k-1) = 6/(k-2) // - 6/(k-2)

4/(k-1)-(6/(k-2)) = 0

4/(k-1)-6*(k-2)^-1 = 0

4/(k-1)-6/(k-2) = 0

(4*(k-2))/((k-1)*(k-2))+(-6*(k-1))/((k-1)*(k-2)) = 0

4*(k-2)-6*(k-1) = 0

-2*k-2 = 0

(-2*k-2)/((k-1)*(k-2)) = 0

(-2*k-2)/((k-1)*(k-2)) = 0 // * (k-1)*(k-2)

-2*k-2 = 0

-2*k-2 = 0 // + 2

-2*k = 2 // : -2

k = 2/(-2)

k = -1

k = -1

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