4/(n+2)=7/n

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Solution for 4/(n+2)=7/n equation: 


D( n )

n+2 = 0

n = 0

n+2 = 0

n+2 = 0

n+2 = 0 // - 2

n = -2

n = 0

n = 0

n in (-oo:-2) U (-2:0) U (0:+oo)

4/(n+2) = 7/n // - 7/n

4/(n+2)-(7/n) = 0

4/(n+2)-7*n^-1 = 0

4/(n+2)-7/n = 0

(4*n)/(n*(n+2))+(-7*(n+2))/(n*(n+2)) = 0

4*n-7*(n+2) = 0

-3*n-14 = 0

(-3*n-14)/(n*(n+2)) = 0

(-3*n-14)/(n*(n+2)) = 0 // * n*(n+2)

-3*n-14 = 0

-3*n-14 = 0 // + 14

-3*n = 14 // : -3

n = 14/(-3)

n = -14/3

n = -14/3

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