4/(v-1)=-6+(5/(v+2))

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Solution for 4/(v-1)=-6+(5/(v+2)) equation: 


D( v )

v-1 = 0

v+2 = 0

v-1 = 0

v-1 = 0

v-1 = 0 // + 1

v = 1

v+2 = 0

v+2 = 0

v+2 = 0 // - 2

v = -2

v in (-oo:-2) U (-2:1) U (1:+oo)

4/(v-1) = 5/(v+2)-6 // - 5/(v+2)-6

4/(v-1)-(5/(v+2))+6 = 0

4/(v-1)-5*(v+2)^-1+6 = 0

4/(v-1)-5/(v+2)+6 = 0

(4*(v+2))/((v-1)*(v+2))+(-5*(v-1))/((v-1)*(v+2))+(6*(v-1)*(v+2))/((v-1)*(v+2)) = 0

4*(v+2)-5*(v-1)+6*(v-1)*(v+2) = 0

6*v^2-v+6*v-12+13 = 0

6*v^2+5*v+1 = 0

6*v^2+5*v+1 = 0

6*v^2+5*v+1 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

v = (1^(1/2)-5)/(2*6) or v = (-1^(1/2)-5)/(2*6)

v = -1/3 or v = -1/2

(v+1/2)*(v+1/3) = 0

((v+1/2)*(v+1/3))/((v-1)*(v+2)) = 0

((v+1/2)*(v+1/3))/((v-1)*(v+2)) = 0 // * (v-1)*(v+2)

(v+1/2)*(v+1/3) = 0

( v+1/2 )

v+1/2 = 0 // - 1/2

v = -1/2

( v+1/3 )

v+1/3 = 0 // - 1/3

v = -1/3

v in { -1/2, -1/3 }

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