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4/(x+2)-6/(2x)=5/(2x+4)
We move all terms to the left:
4/(x+2)-6/(2x)-(5/(2x+4))=0
Domain of the equation: (x+2)!=0
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: (2x+4))!=0We calculate fractions
x∈R
(8x^2*()/((x+2)*2x*(2x+4)))+(-6*(x+2)*(2x+4)))/((x+2)*2x*(2x+4)))+(-(5*(x+2)*2x)/((x+2)*2x*(2x+4)))=0
We calculate terms in parentheses: +(8x^2*()/((x+2)*2x*(2x+4))), so:
8x^2*()/((x+2)*2x*(2x+4))
We multiply all the terms by the denominator
8x^2*()
Back to the equation:
+(8x^2*())
We calculate terms in parentheses: +(-6*(x+2)*(2x+4)))/((x+2)*2x*(2x+4)))+(-(5*(x+2)*2x)/((x+2)*2x*(2x+4))), so:
-6*(x+2)*(2x+4)))/((x+2)*2x*(2x+4)))+(-(5*(x+2)*2x)/((x+2)*2x*(2x+4))
We add all the numbers together, and all the variables
-6*(x+2)*(2x+4)))/((x+2)*2x*(2x+4)))+(-(5*(x+2)*2x)/((x+2)*2x*(2x
We multiply all the terms by the denominator
-6*(x+2)*(2x+4)))+2*2x*2x*((x+4))+(-(5*x*((x+2)*2x)+2*2x*2x*((x
Wy multiply elements
8x^3*2-6*(x+2)*(2x+4)))+2*2x*2x*((x+4))+(-(5*x*((x+2)*2x)
We do not support expression: x^3
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