4/(x+3)=5/(2x-3)

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Solution for 4/(x+3)=5/(2x-3) equation: 



4/(x+3)=5/(2x-3)

We move all terms to the left:

4/(x+3)-(5/(2x-3))=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (2x-3))!=0

x∈R



We calculate fractions


8x/((x+3)*(2x-3)))+(-(5*(x+3))/((x+3)*(2x-3)))=0



We calculate terms in parentheses: -(5*(x+3))/((x+3)*(2x-3))), so:

5*(x+3))/((x+3)*(2x-3))

We multiply all the terms by the denominator


5*(x+3))

We multiply parentheses

5x+

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We add all the numbers together, and all the variables

-5x+8x/((x+3)*(2x-3)))+(=0

We multiply all the terms by the denominator


-5x*((x+3)*(2x-3)))+(+8x=0

We add all the numbers together, and all the variables

8x-5x*((x+3)*(2x-3)))+(=0

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