4/(x-1)=-6+(5/(x+2))

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Solution for 4/(x-1)=-6+(5/(x+2)) equation:


D( x )

x+2 = 0

x-1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-2) U (-2:1) U (1:+oo)

4/(x-1) = 5/(x+2)-6 // - 5/(x+2)-6

4/(x-1)-(5/(x+2))+6 = 0

4/(x-1)-5*(x+2)^-1+6 = 0

4/(x-1)-5/(x+2)+6 = 0

(4*(x+2))/((x-1)*(x+2))+(-5*(x-1))/((x-1)*(x+2))+(6*(x-1)*(x+2))/((x-1)*(x+2)) = 0

4*(x+2)-5*(x-1)+6*(x-1)*(x+2) = 0

6*x^2-x+6*x-12+13 = 0

6*x^2+5*x+1 = 0

6*x^2+5*x+1 = 0

6*x^2+5*x+1 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(2*6) or x = (-1^(1/2)-5)/(2*6)

x = -1/3 or x = -1/2

(x+1/2)*(x+1/3) = 0

((x+1/2)*(x+1/3))/((x-1)*(x+2)) = 0

((x+1/2)*(x+1/3))/((x-1)*(x+2)) = 0 // * (x-1)*(x+2)

(x+1/2)*(x+1/3) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x+1/3 )

x+1/3 = 0 // - 1/3

x = -1/3

x in { -1/2, -1/3 }

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