4/(x-2)=x/12

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Solution for 4/(x-2)=x/12 equation:


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

4/(x-2) = x/12 // - x/12

4/(x-2)-(x/12) = 0

4/(x-2)-x/12 = 0

(4*12)/(12*(x-2))+(-x*(x-2))/(12*(x-2)) = 0

4*12-x*(x-2) = 0

2*x-x^2+48 = 0

2*x-x^2+48 = 0

2*x-x^2+48 = 0

DELTA = 2^2-(-1*4*48)

DELTA = 196

DELTA > 0

x = (196^(1/2)-2)/(-1*2) or x = (-196^(1/2)-2)/(-1*2)

x = -6 or x = 8

(x+6)*(x-8) = 0

((x+6)*(x-8))/(12*(x-2)) = 0

((x+6)*(x-8))/(12*(x-2)) = 0 // * 12*(x-2)

(x+6)*(x-8) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-8 )

x-8 = 0 // + 8

x = 8

x in { -6, 8 }

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