4/(x-3)=-3/(x+5)+18/(x-3)(x+5)

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Solution for 4/(x-3)=-3/(x+5)+18/(x-3)(x+5) equation: 


D( x )

x+5 = 0

x-3 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:-5) U (-5:3) U (3:+oo)

4/(x-3) = (18/(x-3))*(x+5)-3/(x+5) // - (18/(x-3))*(x+5)-3/(x+5)

4/(x-3)-(-3/(x+5))-((18/(x-3))*(x+5)) = 0

4/(x-3)+3*(x+5)^-1-18*(x-3)^-1*(x+5) = 0

4/(x-3)+3/(x+5)+(-18*(x+5))/(x-3) = 0

(4*(x+5))/((x-3)*(x+5))+(3*(x-3))/((x-3)*(x+5))+(-18*(x+5)^2)/((x-3)*(x+5)) = 0

4*(x+5)+3*(x-3)-18*(x+5)^2 = 0

7*x-18*x^2-180*x-450+11 = 0

-18*x^2-173*x-439 = 0

-18*x^2-173*x-439 = 0

-1*(18*x^2+173*x+439) = 0

18*x^2+173*x+439 = 0

DELTA = 173^2-(4*18*439)

DELTA = -1679

DELTA < 0

-1 = 0

-1/((x-3)*(x+5)) = 0

-1/((x-3)*(x+5)) = 0 // * (x-3)*(x+5)

-1 = 0

x belongs to the empty set

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