4/(x-3)=-6/(x+3)+14/(x-3)(x+3)

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Solution for 4/(x-3)=-6/(x+3)+14/(x-3)(x+3) equation: 


D( x )

x-3 = 0

x+3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

4/(x-3) = (14/(x-3))*(x+3)-6/(x+3) // - (14/(x-3))*(x+3)-6/(x+3)

4/(x-3)-(-6/(x+3))-((14/(x-3))*(x+3)) = 0

4/(x-3)+6*(x+3)^-1-14*(x-3)^-1*(x+3) = 0

4/(x-3)+6/(x+3)+(-14*(x+3))/(x-3) = 0

(4*(x+3))/((x-3)*(x+3))+(6*(x-3))/((x-3)*(x+3))+(-14*(x+3)^2)/((x-3)*(x+3)) = 0

4*(x+3)+6*(x-3)-14*(x+3)^2 = 0

10*x-14*x^2-84*x-126-6 = 0

-14*x^2-74*x-132 = 0

-14*x^2-74*x-132 = 0

-2*(7*x^2+37*x+66) = 0

7*x^2+37*x+66 = 0

DELTA = 37^2-(4*7*66)

DELTA = -479

DELTA < 0

-2 = 0

-2/((x-3)*(x+3)) = 0

-2/((x-3)*(x+3)) = 0 // * (x-3)*(x+3)

-2 = 0

x belongs to the empty set

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