4/(x-3)=16/(x-2)

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Solution for 4/(x-3)=16/(x-2) equation: 


D( x )

x-2 = 0

x-3 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:2) U (2:3) U (3:+oo)

4/(x-3) = 16/(x-2) // - 16/(x-2)

4/(x-3)-(16/(x-2)) = 0

4/(x-3)-16*(x-2)^-1 = 0

4/(x-3)-16/(x-2) = 0

(4*(x-2))/((x-3)*(x-2))+(-16*(x-3))/((x-3)*(x-2)) = 0

4*(x-2)-16*(x-3) = 0

40-12*x = 0

(40-12*x)/((x-3)*(x-2)) = 0

(40-12*x)/((x-3)*(x-2)) = 0 // * (x-3)*(x-2)

40-12*x = 0

40-12*x = 0 // - 40

-12*x = -40 // : -12

x = -40/(-12)

x = 10/3

x = 10/3

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