4/(z+3)=2/(z-2)

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Solution for 4/(z+3)=2/(z-2) equation: 


D( z )

z+3 = 0

z-2 = 0

z+3 = 0

z+3 = 0

z+3 = 0 // - 3

z = -3

z-2 = 0

z-2 = 0

z-2 = 0 // + 2

z = 2

z in (-oo:-3) U (-3:2) U (2:+oo)

4/(z+3) = 2/(z-2) // - 2/(z-2)

4/(z+3)-(2/(z-2)) = 0

4/(z+3)-2*(z-2)^-1 = 0

4/(z+3)-2/(z-2) = 0

(4*(z-2))/((z+3)*(z-2))+(-2*(z+3))/((z+3)*(z-2)) = 0

4*(z-2)-2*(z+3) = 0

2*z-14 = 0

(2*z-14)/((z+3)*(z-2)) = 0

(2*z-14)/((z+3)*(z-2)) = 0 // * (z+3)*(z-2)

2*z-14 = 0

2*z-14 = 0 // + 14

2*z = 14 // : 2

z = 14/2

z = 7

z = 7

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