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4/10x-x=-12
We move all terms to the left:
4/10x-x-(-12)=0
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
-1x+4/10x+12=0
We multiply all the terms by the denominator
-1x*10x+12*10x+4=0
Wy multiply elements
-10x^2+120x+4=0
a = -10; b = 120; c = +4;
Δ = b2-4ac
Δ = 1202-4·(-10)·4
Δ = 14560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14560}=\sqrt{16*910}=\sqrt{16}*\sqrt{910}=4\sqrt{910}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-4\sqrt{910}}{2*-10}=\frac{-120-4\sqrt{910}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+4\sqrt{910}}{2*-10}=\frac{-120+4\sqrt{910}}{-20} $
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