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4/10x=5x-1
We move all terms to the left:
4/10x-(5x-1)=0
Domain of the equation: 10x!=0We get rid of parentheses
x!=0/10
x!=0
x∈R
4/10x-5x+1=0
We multiply all the terms by the denominator
-5x*10x+1*10x+4=0
Wy multiply elements
-50x^2+10x+4=0
a = -50; b = 10; c = +4;
Δ = b2-4ac
Δ = 102-4·(-50)·4
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*-50}=\frac{-40}{-100} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*-50}=\frac{20}{-100} =-1/5 $
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