4/12y+3/12=5/12

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Solution for 4/12y+3/12=5/12 equation: 



4/12y+3/12=5/12

We move all terms to the left:

4/12y+3/12-(5/12)=0



Domain of the equation: 12y!=0

y!=0/12

y!=0

y∈R



We add all the numbers together, and all the variables

4/12y+3/12-(+5/12)=0

We get rid of parentheses

4/12y+3/12-5/12=0

We calculate fractions


=0

y=0/1

y=0

Równanie nie ma rozwiązania

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