4/13=2b/13+6b/2b

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Solution for 4/13=2b/13+6b/2b equation: 


b in (-oo:+oo)

4/13 = ((6*b)/2)*b+(2*b)/13 // - ((6*b)/2)*b+(2*b)/13

4/13-(((6*b)/2)*b)-((2*b)/13) = 0

(-2/13)*b-3*b^2+4/13 = 0

4/13-3*b^2-2/13*b = 0

DELTA = (-2/13)^2-(-3*4/13*4)

DELTA = 628/169

DELTA > 0

b = ((628/169)^(1/2)+2/13)/(-3*2) or b = (2/13-(628/169)^(1/2))/(-3*2)

b = ((628/169)^(1/2)+2/13)/(-6) or b = (2/13-(628/169)^(1/2))/(-6)

b in { ((628/169)^(1/2)+2/13)/(-6), (2/13-(628/169)^(1/2))/(-6) }

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