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4/15=2/5z
We move all terms to the left:
4/15-(2/5z)=0
Domain of the equation: 5z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
-(+2/5z)+4/15=0
We get rid of parentheses
-2/5z+4/15=0
We calculate fractions
There is no solution for this equation
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