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4/1x+2=3/8x-4
We move all terms to the left:
4/1x+2-(3/8x-4)=0
Domain of the equation: 1x!=0
x∈R
Domain of the equation: 8x-4)!=0We get rid of parentheses
x∈R
4/1x-3/8x+4+2=0
We calculate fractions
32x/8x^2+(-3x)/8x^2+4+2=0
We add all the numbers together, and all the variables
32x/8x^2+(-3x)/8x^2+6=0
We multiply all the terms by the denominator
32x+(-3x)+6*8x^2=0
Wy multiply elements
48x^2+32x+(-3x)=0
We get rid of parentheses
48x^2+32x-3x=0
We add all the numbers together, and all the variables
48x^2+29x=0
a = 48; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·48·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*48}=\frac{-58}{96} =-29/48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*48}=\frac{0}{96} =0 $
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