4/2c-7=1/10c

Solution for 4/2c-7=1/10c equation:

4/2c-7=1/10c

We move all terms to the left:

4/2c-7-(1/10c)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



Domain of the equation: 10c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

4/2c-(+1/10c)-7=0

We get rid of parentheses

4/2c-1/10c-7=0

We calculate fractions


40c/20c^2+(-2c)/20c^2-7=0

We multiply all the terms by the denominator


40c+(-2c)-7*20c^2=0

Wy multiply elements

-140c^2+40c+(-2c)=0

We get rid of parentheses

-140c^2+40c-2c=0

We add all the numbers together, and all the variables

-140c^2+38c=0

a = -140; b = 38; c = 0;
Δ = b2-4ac
Δ = 382-4·(-140)·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-38}{2*-140}=\frac{-76}{-280}
=19/70
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+38}{2*-140}=\frac{0}{-280}
=0
$