4/2x+8=2/3x

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Solution for 4/2x+8=2/3x equation:



4/2x+8=2/3x
We move all terms to the left:
4/2x+8-(2/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
4/2x-(+2/3x)+8=0
We get rid of parentheses
4/2x-2/3x+8=0
We calculate fractions
12x/6x^2+(-4x)/6x^2+8=0
We multiply all the terms by the denominator
12x+(-4x)+8*6x^2=0
Wy multiply elements
48x^2+12x+(-4x)=0
We get rid of parentheses
48x^2+12x-4x=0
We add all the numbers together, and all the variables
48x^2+8x=0
a = 48; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·48·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*48}=\frac{-16}{96} =-1/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*48}=\frac{0}{96} =0 $

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