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4/2x=64x
We move all terms to the left:
4/2x-(64x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-64x+4/2x=0
We multiply all the terms by the denominator
-64x*2x+4=0
Wy multiply elements
-128x^2+4=0
a = -128; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-128)·4
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{2}}{2*-128}=\frac{0-32\sqrt{2}}{-256} =-\frac{32\sqrt{2}}{-256} =-\frac{\sqrt{2}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{2}}{2*-128}=\frac{0+32\sqrt{2}}{-256} =\frac{32\sqrt{2}}{-256} =\frac{\sqrt{2}}{-8} $
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