4/2y+35=3

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Solution for 4/2y+35=3 equation: 



4/2y+35=3

We move all terms to the left:

4/2y+35-(3)=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

4/2y+32=0

We multiply all the terms by the denominator


32*2y+4=0

Wy multiply elements

64y+4=0

We move all terms containing y to the left, all other terms to the right

64y=-4

y=-4/64

y=-1/16

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