4/3(b-5)=24

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Solution for 4/3(b-5)=24 equation: 



4/3(b-5)=24

We move all terms to the left:

4/3(b-5)-(24)=0



Domain of the equation: 3(b-5)!=0

b∈R



We multiply all the terms by the denominator


-24*3(b-5)+4=0

Wy multiply elements

-72b(b+4=0

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