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4/3(x+2)-2/3x=1/(x+2)
We move all terms to the left:
4/3(x+2)-2/3x-(1/(x+2))=0
Domain of the equation: 3(x+2)!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
(-6x^2x/(3(x+2)*3x*(x+2)))+(12x^2*()/(3(x+2)*3x*(x+2)))+(-(1*3(x+2)*3x)/(3(x+2)*3x*(x+2)))=0
We calculate terms in parentheses: +(-6x^2x/(3(x+2)*3x*(x+2))), so:
-6x^2x/(3(x+2)*3x*(x+2))
We multiply all the terms by the denominator
-6x^2x
Back to the equation:
+(-6x^2x)
We calculate terms in parentheses: +(12x^2*()/(3(x+2)*3x*(x+2))), so:
12x^2*()/(3(x+2)*3x*(x+2))
We multiply all the terms by the denominator
12x^2*()
Back to the equation:
+(12x^2*())
We calculate terms in parentheses: +(-(1*3(x+2)*3x)/(3(x+2)*3x*(x+2))), so:determiningTheFunctionDomain (-6x^2x)+(-9x^2x+(12x^2*())=0
-(1*3(x+2)*3x)/(3(x+2)*3x*(x+2))
We multiply all the terms by the denominator
-(1*3(x+2)*3x)
We calculate terms in parentheses: -(1*3(x+2)*3x), so:Back to the equation:
1*3(x+2)*3x
Wy multiply elements
9x^2(x
Back to the equation:
-(9x^2(x)
+(-(9x^2x)
We get rid of parentheses
-6x^2x+(-9x^2x+(12x^2*())=0
We calculate terms in parentheses: +(-9x^2x+(12x^2*()), so:
-9x^2x+(12x^2*()
We calculate terms in parentheses: +(12x^2*(), so:
12x^2*(
We calculate terms in parentheses: +(12x^2*(), so:
12x^2*(
We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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We calculate terms in parentheses: +(12x^2*(), so:
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