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4/3(x+2)=2/3x=1/x+2
We move all terms to the left:
4/3(x+2)-(2/3x)=0
Domain of the equation: 3(x+2)!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/3(x+2)-(+2/3x)=0
We get rid of parentheses
4/3(x+2)-2/3x=0
We calculate fractions
12x/(9x^2+18x)+(-6xx/(9x^2+18x)=0
We calculate terms in parentheses: +(-6xx/(9x^2+18x), so:We get rid of parentheses
-6xx/(9x^2+18x
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
12x/(9x^2+18x)-6xx=0
We multiply all the terms by the denominator
12x-6xx*(9x^2+18x)=0
We multiply parentheses
-54x^3-108x^2+12x=0
We do not support expression: x^3
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