4/3(x+8)=3/4(2x+12)

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Solution for 4/3(x+8)=3/4(2x+12) equation: 



4/3(x+8)=3/4(2x+12)

We move all terms to the left:

4/3(x+8)-(3/4(2x+12))=0



Domain of the equation: 3(x+8)!=0

x∈R





Domain of the equation: 4(2x+12))!=0

x∈R



We calculate fractions


(16x2/(3(x+8)*4(2x+12)))+(-9xx/(3(x+8)*4(2x+12)))=0



We calculate terms in parentheses: +(16x2/(3(x+8)*4(2x+12))), so:

16x2/(3(x+8)*4(2x+12))

We multiply all the terms by the denominator


16x2

We add all the numbers together, and all the variables

16x^2

Back to the equation:

+(16x^2)





We calculate terms in parentheses: +(-9xx/(3(x+8)*4(2x+12))), so:

-9xx/(3(x+8)*4(2x+12))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

16x^2-9xx=0

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