4/3*v-11/4*v=-17/5

Solution for 4/3*v-11/4*v=-17/5 equation:

4/3v-11/4v=-17/5

We move all terms to the left:

4/3v-11/4v-(-17/5)=0


Domain of the equation: 3v!=0

v!=0/3

v!=0

v∈R



Domain of the equation: 4v!=0

v!=0/4

v!=0

v∈R


We get rid of parentheses

4/3v-11/4v+17/5=0

We calculate fractions


816v^2/300v^2+400v/300v^2+(-825v)/300v^2=0

We multiply all the terms by the denominator


816v^2+400v+(-825v)=0

We get rid of parentheses

816v^2+400v-825v=0

We add all the numbers together, and all the variables

816v^2-425v=0

a = 816; b = -425; c = 0;
Δ = b2-4ac
Δ = -4252-4·816·0
Δ = 180625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{180625}=425$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-425}{2*816}=\frac{0}{1632}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+425}{2*816}=\frac{850}{1632}
=25/48
$