4/3+2/(y+1)+5(3y+3)

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Solution for 4/3+2/(y+1)+5(3y+3) equation: 


D( y )

y+1 = 0

y+1 = 0

y+1 = 0

y+1 = 0 // - 1

y = -1

y in (-oo:-1) U (-1:+oo)

2/(y+1)+5*(3*y+3)+4/3 = 0

(2*3)/(3*(y+1))+(3*5*(3*y+3)*(y+1))/(3*(y+1))+(4*(y+1))/(3*(y+1)) = 0

3*5*(3*y+3)*(y+1)+4*(y+1)+2*3 = 0

45*y^2+90*y+4*y+4+51 = 0

45*y^2+94*y+55 = 0

45*y^2+94*y+55 = 0

45*y^2+94*y+55 = 0

DELTA = 94^2-(4*45*55)

DELTA = -1064

DELTA < 0

1 = 0

1/(3*(y+1)) = 0

1/(3*(y+1)) = 0 // * 3*(y+1)

1 = 0

y belongs to the empty set

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