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4/3+2x=19/12+x
We move all terms to the left:
4/3+2x-(19/12+x)=0
Domain of the equation: 12+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-12
x!=-12/1
x!=-12
x∈R
2x-(+x+19/12)+4/3=0
We get rid of parentheses
2x-x-19/12+4/3=0
We calculate fractions
There is no solution for this equation
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