4/3=(n-4)/6

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Solution for 4/3=(n-4)/6 equation: 



4/3=(n-4)/6

We move all terms to the left:

4/3-((n-4)/6)=0

We calculate fractions


(-((n-4)*3)/()+()/()=0



We calculate terms in parentheses: +(-((n-4)*3)/()+()/(), so:

-((n-4)*3)/()+()/(

We add all the numbers together, and all the variables

-((n-4)*3)/()+1

We multiply all the terms by the denominator


-((n-4)*3)+1*()



We calculate terms in parentheses: -((n-4)*3), so:

(n-4)*3

We multiply parentheses

3n-12

Back to the equation:

-(3n-12)



We add all the numbers together, and all the variables

-(3n-12)

We get rid of parentheses

-3n+12

Back to the equation:

+(-3n+12)



We get rid of parentheses

-3n+12=0

We move all terms containing n to the left, all other terms to the right

-3n=-12

n=-12/-3

n=+4

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