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4/3=2/12j
We move all terms to the left:
4/3-(2/12j)=0
Domain of the equation: 12j)!=0We add all the numbers together, and all the variables
j!=0/1
j!=0
j∈R
-(+2/12j)+4/3=0
We get rid of parentheses
-2/12j+4/3=0
We calculate fractions
There is no solution for this equation
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