4/3=n-4/n

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Solution for 4/3=n-4/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4/3 = n-(4/n) // - n-(4/n)

4/n-n+4/3 = 0

4*n^-1-1*n^1+4/3*n^0 = 0

(4/3*n^1-1*n^2+4*n^0)/(n^1) = 0 // * n^2

n^1*(4/3*n^1-1*n^2+4*n^0) = 0

n^1

(4/3)*n-n^2+4 = 0

(4/3)*n-n^2+4 = 0

DELTA = (4/3)^2-(-1*4*4)

DELTA = 160/9

DELTA > 0

n = ((160/9)^(1/2)-(4/3))/(-1*2) or n = (-(4/3)-(160/9)^(1/2))/(-1*2)

n = ((160/9)^(1/2)-4/3)/(-2) or n = ((160/9)^(1/2)+4/3)/2

n in { ((160/9)^(1/2)-4/3)/(-2), ((160/9)^(1/2)+4/3)/2} 

n in { ((160/9)^(1/2)-4/3)/(-2), ((160/9)^(1/2)+4/3)/2 }

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