4/3b+6/b=11

Solution for 4/3b+6/b=11 equation:

4/3b+6/b=11

We move all terms to the left:

4/3b+6/b-(11)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



Domain of the equation: b!=0

b∈R


We calculate fractions


4b/3b^2+18b/3b^2-11=0

We multiply all the terms by the denominator


4b+18b-11*3b^2=0

We add all the numbers together, and all the variables

22b-11*3b^2=0

Wy multiply elements

-33b^2+22b=0

a = -33; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-33)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-33}=\frac{-44}{-66}
=2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-33}=\frac{0}{-66}
=0
$