4/3b-11=25b=

Solution for 4/3b-11=25b= equation:

4/3b-11=25b=

We move all terms to the left:

4/3b-11-(25b)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We add all the numbers together, and all the variables

-25b+4/3b-11=0

We multiply all the terms by the denominator


-25b*3b-11*3b+4=0

Wy multiply elements

-75b^2-33b+4=0

a = -75; b = -33; c = +4;
Δ = b2-4ac
Δ = -332-4·(-75)·4
Δ = 2289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{2289}}{2*-75}=\frac{33-\sqrt{2289}}{-150}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{2289}}{2*-75}=\frac{33+\sqrt{2289}}{-150}
$