4/3e-17-5/6e=11

Solution for 4/3e-17-5/6e=11 equation:

4/3e-17-5/6e=11

We move all terms to the left:

4/3e-17-5/6e-(11)=0


Domain of the equation: 3e!=0

e!=0/3

e!=0

e∈R



Domain of the equation: 6e!=0

e!=0/6

e!=0

e∈R


We add all the numbers together, and all the variables

4/3e-5/6e-28=0

We calculate fractions


24e/18e^2+(-15e)/18e^2-28=0

We multiply all the terms by the denominator


24e+(-15e)-28*18e^2=0

Wy multiply elements

-504e^2+24e+(-15e)=0

We get rid of parentheses

-504e^2+24e-15e=0

We add all the numbers together, and all the variables

-504e^2+9e=0

a = -504; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-504)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-504}=\frac{-18}{-1008}
=1/56
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-504}=\frac{0}{-1008}
=0
$