4/3e-5/9e-17=11

Solution for 4/3e-5/9e-17=11 equation:

4/3e-5/9e-17=11

We move all terms to the left:

4/3e-5/9e-17-(11)=0


Domain of the equation: 3e!=0

e!=0/3

e!=0

e∈R



Domain of the equation: 9e!=0

e!=0/9

e!=0

e∈R


We add all the numbers together, and all the variables

4/3e-5/9e-28=0

We calculate fractions


36e/27e^2+(-15e)/27e^2-28=0

We multiply all the terms by the denominator


36e+(-15e)-28*27e^2=0

Wy multiply elements

-756e^2+36e+(-15e)=0

We get rid of parentheses

-756e^2+36e-15e=0

We add all the numbers together, and all the variables

-756e^2+21e=0

a = -756; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-756)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-756}=\frac{-42}{-1512}
=1/36
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-756}=\frac{0}{-1512}
=0
$