4/3h=12,h=16

Solution for 4/3h=12,h=16 equation:

4/3h=12.h=16

We move all terms to the left:

4/3h-(12.h)=0


Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R


We add all the numbers together, and all the variables

4/3h-(+12.h)=0

We get rid of parentheses

4/3h-12.h=0

We multiply all the terms by the denominator


-(12.h)*3h+4=0

We add all the numbers together, and all the variables

-(+12.h)*3h+4=0

We multiply parentheses

-36h^2+4=0

a = -36; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-36)·4
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-36}=\frac{-24}{-72}
=1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-36}=\frac{24}{-72}
=-1/3
$