4/3m-2=5-8/m

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Solution for 4/3m-2=5-8/m equation:


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(4/3)*m-2 = 5-(8/m) // - 5-(8/m)

(4/3)*m+8/m-5-2 = 0

4/3*m^1+8*m^-1-7*m^0 = 0

(4/3*m^2-7*m^1+8*m^0)/(m^1) = 0 // * m^2

m^1*(4/3*m^2-7*m^1+8*m^0) = 0

m^1

(4/3)*m^2-7*m+8 = 0

(4/3)*m^2-7*m+8 = 0

DELTA = (-7)^2-(4*8*(4/3))

DELTA = 19/3

DELTA > 0

m = ((19/3)^(1/2)+7)/(2*(4/3)) or m = (7-(19/3)^(1/2))/(2*(4/3))

m = 3/8*((19/3)^(1/2)+7) or m = 3/8*(7-(19/3)^(1/2))

m in { 3/8*(7-(19/3)^(1/2)), 3/8*((19/3)^(1/2)+7)}

m in { 3/8*(7-(19/3)^(1/2)), 3/8*((19/3)^(1/2)+7) }

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