4/3t+(8-5)=7

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Solution for 4/3t+(8-5)=7 equation: 



4/3t+(8-5)=7

We move all terms to the left:

4/3t+(8-5)-(7)=0



Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R



determiningTheFunctionDomain
4/3t-7+(8-5)=0

We add all the numbers together, and all the variables

4/3t-7+3=0

We add all the numbers together, and all the variables

4/3t-4=0

We multiply all the terms by the denominator


-4*3t+4=0

Wy multiply elements

-12t+4=0

We move all terms containing t to the left, all other terms to the right

-12t=-4

t=-4/-12

t=1/3

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