4/3t-(t+4)/6=1/3(3t-4)

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Solution for 4/3t-(t+4)/6=1/3(3t-4) equation: 



4/3t-(t+4)/6=1/3(3t-4)

We move all terms to the left:

4/3t-(t+4)/6-(1/3(3t-4))=0



Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R





Domain of the equation: 3(3t-4))!=0

t∈R



We calculate fractions


216t/162t^2+(-(t+4)*3t*3(3t-4)))/162t^2+(-(1*3t*6)/162t^2=0

We add all the numbers together, and all the variables

216t/162t^2+(-(t+4)*3t*3(3t-4)))/162t^2+(-(+1*3t*6)/162t^2=0

We calculate fractions

We do not support etpression: t^4

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