4/3w-1/2w-4=12

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Solution for 4/3w-1/2w-4=12 equation:



4/3w-1/2w-4=12
We move all terms to the left:
4/3w-1/2w-4-(12)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: 2w!=0
w!=0/2
w!=0
w∈R
We add all the numbers together, and all the variables
4/3w-1/2w-16=0
We calculate fractions
8w/6w^2+(-3w)/6w^2-16=0
We multiply all the terms by the denominator
8w+(-3w)-16*6w^2=0
Wy multiply elements
-96w^2+8w+(-3w)=0
We get rid of parentheses
-96w^2+8w-3w=0
We add all the numbers together, and all the variables
-96w^2+5w=0
a = -96; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-96)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-96}=\frac{-10}{-192} =5/96 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-96}=\frac{0}{-192} =0 $

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