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4/3w-2/w=1
We move all terms to the left:
4/3w-2/w-(1)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: w!=0We calculate fractions
w∈R
4w/3w^2+(-6w)/3w^2-1=0
We multiply all the terms by the denominator
4w+(-6w)-1*3w^2=0
Wy multiply elements
-3w^2+4w+(-6w)=0
We get rid of parentheses
-3w^2+4w-6w=0
We add all the numbers together, and all the variables
-3w^2-2w=0
a = -3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-3)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-3}=\frac{0}{-6} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-3}=\frac{4}{-6} =-2/3 $
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