4/3x+11=-3/4x

Solution for 4/3x+11=-3/4x equation:

4/3x+11=-3/4x

We move all terms to the left:

4/3x+11-(-3/4x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

4/3x+3/4x+11=0

We calculate fractions


16x/12x^2+9x/12x^2+11=0

We multiply all the terms by the denominator


16x+9x+11*12x^2=0

We add all the numbers together, and all the variables

25x+11*12x^2=0

Wy multiply elements

132x^2+25x=0

a = 132; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·132·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*132}=\frac{-50}{264}
=-25/132
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*132}=\frac{0}{264}
=0
$