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4/3x+2x=60
We move all terms to the left:
4/3x+2x-(60)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x+4/3x-60=0
We multiply all the terms by the denominator
2x*3x-60*3x+4=0
Wy multiply elements
6x^2-180x+4=0
a = 6; b = -180; c = +4;
Δ = b2-4ac
Δ = -1802-4·6·4
Δ = 32304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32304}=\sqrt{16*2019}=\sqrt{16}*\sqrt{2019}=4\sqrt{2019}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-4\sqrt{2019}}{2*6}=\frac{180-4\sqrt{2019}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+4\sqrt{2019}}{2*6}=\frac{180+4\sqrt{2019}}{12} $
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