4/3x+7/6x=48/9

Solution for 4/3x+7/6x=48/9 equation:

4/3x+7/6x=48/9

We move all terms to the left:

4/3x+7/6x-(48/9)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x+7/6x-(+48/9)=0

We get rid of parentheses

4/3x+7/6x-48/9=0

We calculate fractions


(-5184x^2)/1458x^2+1944x/1458x^2+1701x/1458x^2=0

We multiply all the terms by the denominator


(-5184x^2)+1944x+1701x=0

We add all the numbers together, and all the variables

(-5184x^2)+3645x=0

We get rid of parentheses

-5184x^2+3645x=0

a = -5184; b = 3645; c = 0;
Δ = b2-4ac
Δ = 36452-4·(-5184)·0
Δ = 13286025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13286025}=3645$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3645)-3645}{2*-5184}=\frac{-7290}{-10368}
=45/64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3645)+3645}{2*-5184}=\frac{0}{-10368}
=0
$