4/3x-10=1/2x+2

Solution for 4/3x-10=1/2x+2 equation:

4/3x-10=1/2x+2

We move all terms to the left:

4/3x-10-(1/2x+2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x+2)!=0

x∈R


We get rid of parentheses

4/3x-1/2x-2-10=0

We calculate fractions


8x/6x^2+(-3x)/6x^2-2-10=0

We add all the numbers together, and all the variables

8x/6x^2+(-3x)/6x^2-12=0

We multiply all the terms by the denominator


8x+(-3x)-12*6x^2=0

Wy multiply elements

-72x^2+8x+(-3x)=0

We get rid of parentheses

-72x^2+8x-3x=0

We add all the numbers together, and all the variables

-72x^2+5x=0

a = -72; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-72)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-72}=\frac{-10}{-144}
=5/72
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-72}=\frac{0}{-144}
=0
$