4/3x-2/x=5

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Solution for 4/3x-2/x=5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x-(2/x) = 5 // - 5

(4/3)*x-(2/x)-5 = 0

(4/3)*x-2*x^-1-5 = 0

4/3*x^1-2*x^-1-5*x^0 = 0

(4/3*x^2-5*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2-5*x^1-2*x^0) = 0

x^1

(4/3)*x^2-5*x-2 = 0

(4/3)*x^2-5*x-2 = 0

DELTA = (-5)^2-(-2*4*(4/3))

DELTA = 107/3

DELTA > 0

x = ((107/3)^(1/2)+5)/(2*(4/3)) or x = (5-(107/3)^(1/2))/(2*(4/3))

x = 3/8*((107/3)^(1/2)+5) or x = 3/8*(5-(107/3)^(1/2))

x in { 3/8*(5-(107/3)^(1/2)), 3/8*((107/3)^(1/2)+5)}

x in { 3/8*(5-(107/3)^(1/2)), 3/8*((107/3)^(1/2)+5) }

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