4/3x-2=5-8/x

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Solution for 4/3x-2=5-8/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x-2 = 5-(8/x) // - 5-(8/x)

(4/3)*x+8/x-5-2 = 0

4/3*x^1+8*x^-1-7*x^0 = 0

(4/3*x^2-7*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^2-7*x^1+8*x^0) = 0

x^1

(4/3)*x^2-7*x+8 = 0

(4/3)*x^2-7*x+8 = 0

DELTA = (-7)^2-(4*8*(4/3))

DELTA = 19/3

DELTA > 0

x = ((19/3)^(1/2)+7)/(2*(4/3)) or x = (7-(19/3)^(1/2))/(2*(4/3))

x = 3/8*((19/3)^(1/2)+7) or x = 3/8*(7-(19/3)^(1/2))

x in { 3/8*(7-(19/3)^(1/2)), 3/8*((19/3)^(1/2)+7)}

x in { 3/8*(7-(19/3)^(1/2)), 3/8*((19/3)^(1/2)+7) }

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